Can someone explain how this loops through a dictionary?
我有两本字典，我想比较一下它们，看看它们之间有什么不同。我感到困惑的是
一切都很好，我只是不太明白它为什么起作用，它在做什么。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | x = {"#04": 0,"#05": 0,"#07": 0,"#08": 1,"#09": 0,"#10": 0,"#11": 1,"#12": 1,"#14": 1,"#15": 1,"#17": 0,"#18": 1,"#19": 1,"#20": 1} y = {"#04": 1,"#05": 0,"#07": 0,"#08": 1,"#09": 0,"#10": 0,"#11": 1,"#12": 1,"#14": 1,"#15": 0,"#17": 1,"#18": 1,"#19": 0,"#20": 1} dict = {k: x[k] for k in x if y[k] != x[k]} list = [] for k, v in dict.items() if v==0: difference = k + ' became ' + '0' list.append(difference) else: difference = k + ' became ' + '1' list.append(difference) print(list) |
它应该打印
实现的过程是比较两个字典，假设它们都有相同的键(可能
为了快速进行比较并方便下一个代码块，他们决定生成一个只包含具有不同值的键的字典。
为了生成这样的词典，他们使用"词典理解"，这是非常有效的。
现在，这个结构：
1 | d = {k: x[k] for k in x if y[k] != x[k]} |
可重写为：
1 2 3 4 | d = {} for k,v in x: # for each key->value pairs in dictionary x if y[k] != x[k]: # if the corresponding elements are different d[k] = x[k] # store the key->value pair in the new dictionary |
号
你可以用上面的