关于python:xmlrpc服务器有问题

problem with xmlrpc server

我使用xmlrpc服务器运行简单的示例，然后按键盘上的ctrl-c:。

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from SimpleXMLRPCServer import SimpleXMLRPCServer
from time import sleep
import threading,time

class Test(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.test1 = 0
def test(self):
return self.test1

def run(self):
while(1):
time.sleep(1)
self.test1 = self.test1 + 1

ts = Test()
ts.start()
server = SimpleXMLRPCServer(("localhost",8888))
server.register_instance(ts)
server.serve_forever()

按下键盘后出错：

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File"/usr/lib/python2.7/SocketServer.py", line 225, in serve_forever
r, w, e = select.select([self], [], [], poll_interval)
KeyboardInterrupt

客户端

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from xmlrpclib import ServerProxy
r=ServerProxy("http://localhost:8888")
print r.test()

正在等待连接，没有错误或警告。在这种情况下如何断开连接？也许这个例子不正确？

使用方式：

在xmlrpclib.serverproxy超时设置

编辑

这里的答案是不兼容，与Python 2.7。在这一改进的代码(在线测试activepython W7的作品：(2.7)

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import xmlrpclib
import httplib

class TimeoutHTTPConnection(httplib.HTTPConnection):

def __init__(self,host,timeout=10):
httplib.HTTPConnection.__init__(self,host,timeout=timeout)
self.set_debuglevel(99)
#self.sock.settimeout(timeout)

"""
class TimeoutHTTP(httplib.HTTP):
_connection_class = TimeoutHTTPConnection
def set_timeout(self, timeout):
self._conn.timeout = timeout
"""

class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout=10, *l, **kw):
xmlrpclib.Transport.__init__(self,*l,**kw)
self.timeout=timeout

def make_connection(self, host):
conn = TimeoutHTTPConnection(host,self.timeout)
return conn

class TimeoutServerProxy(xmlrpclib.ServerProxy):
def __init__(self,uri,timeout=10,*l,**kw):
kw['transport']=TimeoutTransport(timeout=timeout, use_datetime=kw.get('use_datetime',0))
xmlrpclib.ServerProxy.__init__(self,uri,*l,**kw)

if __name__ =="__main__":
s=TimeoutServerProxy('http://127.0.0.1:8888',timeout=2)
print s.test()