关于javascript:正则表达式验证电子邮件的意外行为

Unexpected behaviour of regex validating email

我正在使用以下regex验证电子邮件地址

1
var regex=/^([A-Za-z0-9_\-\.])+\@([A-Za-z0-9_\-\.])+\.([A-Za-z]{2,4})$/;

现在的问题是它表现出了意想不到的行为

如果我输入电子邮件地址

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pakistan@gmail.com

上面的regex接受它作为电子邮件地址的验证格式。但是当我使用格式

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igz.dwd.08@gmail.com

regex不将其验证为电子邮件格式

同样地

1
abcdef@gmail.com

不是验证格式,

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awaisobaidzaid@gmail.com

是验证电子邮件格式我特别想要格式的电子邮件地址的有效性

1
igz.dwd.08@gmail.com

我在上面犯了什么错误?


由RFC822定义的电子邮件地址(被RFC2822取代)是一个非常复杂的regex。在最初的RFC中,它被定义为递归下降。这使得用正则表达式表达它非常困难。请参阅本"文章":http://www.ex-parrot.com/pdw/mail-rfc822-address.html

在Perl样式的regex中:

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如果您真的想使用javascript+regex进行验证,请尝试这个非常长的验证。我已经用了一段时间了,到目前为止还没有问题。

1
var regex = /^(?:"(?:[^\"]|\\.)+"|[A-Za-z0-9!#$%&'\*\+\-\/=\?^_`{|}~]+(?:\.[A-Za-z0-9!#$%&'\*\+\-\/=\?^_`{|}~]+)*)@(?:[A-Za-z](?:[A-Za-z0-9\-]{0,61}[A-Za-z0-9])?(?:\.[A-Za-z](?:[A-Za-z0-9\-]{0,61}[A-Za-z0-9])?)*|\[(?:(?:2(?:[0-4]\d|5[0-5])|[0-1]?\d{1,2})(?:\.(?:2(?:[0-4]\d|5[0-5])|[0-1]?\d{1,2})){3}|(?:(?:(?:[0-9A-Fa-f]{1,4}\:){1,1}(?:\:[0-9A-Fa-f]{1,4}){1,6})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,2}(?:\:[0-9A-Fa-f]{1,4}){1,5})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,3}(?:\:[0-9A-Fa-f]{1,4}){1,4})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,4}(?:\:[0-9A-Fa-f]{1,4}){1,3})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,5}(?:\:[0-9A-Fa-f]{1,4}){1,2})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,6}(?:\:[0-9A-Fa-f]{1,4}){1,1})|(?:[0-9A-Fa-f]{1,4}(?:\:[0-9A-Fa-f]{1,4}){7})|(?:(?:(?:[0-9A-Fa-f]{1,4}\:){1,7}|\:)\:)|(?:\:(?:\:[0-9A-Fa-f]{1,4}){1,7})|(?:(?:(?:(?:[0-9A-Fa-f]{1,4}\:){6})(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3}))|(?:(?:(?:[0-9A-Fa-f]{1,4}\:){5}[0-9A-Fa-f]{1,4}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3}))|(?:(?:[0-9A-Fa-f]{1,4}\:){5}\:[0-9A-Fa-f]{1,4}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,1}(?:\:[0-9A-Fa-f]{1,4}){1,4}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,2}(?:\:[0-9A-Fa-f]{1,4}){1,3}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,3}(?:\:[0-9A-Fa-f]{1,4}){1,2}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:(?:[0-9A-Fa-f]{1,4}\:){1,4}(?:\:[0-9A-Fa-f]{1,4}){1,1}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:(?:(?:[0-9A-Fa-f]{1,4}\:){1,5}|\:)\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3})|(?:\:(?:\:[0-9A-Fa-f]{1,4}){1,5}\:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3}))(?:\%\d+)?)\])$/;

P.S.它符合RFC822和RFC5322,除了不能在单个纯regex中完成的长度验证。


首先,不要转义字符类中的字符,即[.]表示文字点。不要编码为[\.]

其次,短划线字符必须是字符类中的第一个或最后一个字符,否则它是范围运算符。

尝试此操作:编辑后包含@benroux的w建议

1
var regex=/^([\w.-])+\@([\w.-])+\.([A-Za-z]{2,4})$/

P.S.我测试过,这个regex与"[email protected]"匹配。


对于初学者来说,\w相当于[a-zA-Z0-9_],因此更改它将使regex明显更简单。

埃多克斯1〔5〕

我在你所有的邮件上都试过了,而且效果很好


试试这个

1
/^[\w.-]+@[\w.-]+\.[a-zA-Z]{2,4}$/