即使设置了超时，Python urllib2.urlopen也会无限地冻结脚本

Python urllib2.urlopen freezes script infinitely even though timeout is set

函数urllib2.urlopen冻结。所以我的问题很简单：

为什么即使设置了超时，urlopen也会冻结我的脚本？
我怎样才能访问URL上的数据(在这种情况下：http：//api.own3d.tv/live？channel = .FnaticTV)，而我的Python进程可能永远不会冻结？

这是冻结的部分(在own3d.py中)：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15

# Try three times to make contact
while True:
try:
# Connect to API

# Right here! It freezes here
connection = urllib2.urlopen(request, timeout=10)

xmlstring = connection.read()
except URLError as e:
tries += 1
if tries >= 3:
sys.stderr.write(
'own3dStreamsUpdater: Fatal error: Repeated timeouts')
exit()

这是我的KeyboardInterrupt之后的堆栈跟踪

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27

Traceback (most recent call last):
File"", line 1, in
File"honsapp/own3dStreamsUpdater.py", line 53, in updateStreamInfo
streamInfo = getStreamInfo(stream)
File"honsapp/own3d.py", line 98, in getStreamInfo
connection = urllib2.urlopen(request, timeout=10)
File"/usr/local/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File"/usr/local/lib/python2.7/urllib2.py", line 394, in open
response = self._open(req, data)
File"/usr/local/lib/python2.7/urllib2.py", line 412, in _open
'_open', req)
File"/usr/local/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File"/usr/local/lib/python2.7/urllib2.py", line 1199, in http_open
return self.do_open(httplib.HTTPConnection, req)
File"/usr/local/lib/python2.7/urllib2.py", line 1170, in do_open
r = h.getresponse(buffering=True)
File"/usr/local/lib/python2.7/httplib.py", line 1027, in getresponse
response.begin()
File"/usr/local/lib/python2.7/httplib.py", line 407, in begin
version, status, reason = self._read_status()
File"/usr/local/lib/python2.7/httplib.py", line 365, in _read_status
line = self.fp.readline()
File"/usr/local/lib/python2.7/socket.py", line 447, in readline
data = self._sock.recv(self._rbufsize)
KeyboardInterrupt

编辑

我让我的剧本过夜了。我不知道它花了多长时间(虽然超过五分钟)，但剧本终于放弃并给了我一个堆栈跟踪：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28

Traceback (most recent call last):
File"honsapp/own3dStreamsUpdater.py", line 260, in
newInfo()
File"honsapp/own3dStreamsUpdater.py", line 172, in newInfo
result = updateStreamInfo(stream)
File"honsapp/own3dStreamsUpdater.py", line 53, in updateStreamInfo
streamInfo = getStreamInfo(stream)
File"/root/Dropbox/Projects/honstreams/honsapp/own3d.py", line 98, in getStreamInfo
connection = urllib2.urlopen(request, timeout=10)
File"/usr/local/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File"/usr/local/lib/python2.7/urllib2.py", line 394, in open
response = self._open(req, data)
File"/usr/local/lib/python2.7/urllib2.py", line 412, in _open
'_open', req)
File"/usr/local/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File"/usr/local/lib/python2.7/urllib2.py", line 1199, in http_open
return self.do_open(httplib.HTTPConnection, req)
File"/usr/local/lib/python2.7/urllib2.py", line 1170, in do_open
r = h.getresponse(buffering=True)
File"/usr/local/lib/python2.7/httplib.py", line 1027, in getresponse
response.begin()
File"/usr/local/lib/python2.7/httplib.py", line 407, in begin
version, status, reason = self._read_status()
File"/usr/local/lib/python2.7/httplib.py", line 371, in _read_status
raise BadStatusLine(line)
httplib.BadStatusLine: ''

这个脚本根本不会冻结，但它是一个很好的例子，说明为什么你不应该在疲倦时编码。应该尝试连接到API三次的循环将永远持续，因为我忘了在那里放一个break。

这个问题是如此愚蠢，我不会责怪你删除它。

固定代码：

1
2
3
4
5
6
7
8
9
10
11
12
13

# Try three times to make contact
while True:
try:
# Connect to API
connection = urllib2.urlopen(request, timeout=10)
xmlstring = connection.read()
break
except URLError as e:
tries += 1
if tries >= 3:
sys.stderr.write(
'own3dStreamsUpdater: Fatal error: Repeated timeouts')
exit()