Query a Table's Foreign Key relationships
对于给定的表'foo',我需要一个查询来生成一组具有指向foo的外键的表。 我正在使用Oracle 10G。
这应该工作(或接近):
1 2 3 4 5 6 7 8 | SELECT TABLE_NAME FROM all_constraints WHERE constraint_type='R' AND r_constraint_name IN (SELECT constraint_name FROM all_constraints WHERE constraint_type IN ('P','U') AND TABLE_NAME='<your table here>'); |
以下陈述应该给予孩子及其所有后代。我在Oracle 10数据库上测试过它。
1 2 3 4 5 6 7 8 | SELECT level, main.table_name parent, link.table_name child FROM user_constraints main, user_constraints link WHERE main.constraint_type IN ('P', 'U') AND link.r_constraint_name = main.constraint_name START WITH main.table_name LIKE UPPER('&&table_name') CONNECT BY main.table_name = PRIOR link.table_name ORDER BY level, main.table_name, link.table_name |
以下是如何将Mike的查询更进一步从约束名称中获取列名:
1 2 3 4 5 6 7 8 9 10 | SELECT * FROM user_cons_columns WHERE constraint_name IN ( SELECT constraint_name FROM all_constraints WHERE constraint_type='R' AND r_constraint_name IN (SELECT constraint_name FROM all_constraints WHERE constraint_type IN ('P','U') AND TABLE_NAME='<your table name here>')); |
我知道现在回答有点迟,但无论如何我都要回答,上面的一些答案非常复杂,因此这里更简单。
1 2 3 4 5 6 7 | `SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = 'your table name'` |
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我认为这样做效果更好:
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36选择a.table_name child_table,a.column_name child_column,a.constraint_name,b.table_name parent_table,b.column_name parent_column,来自user_cons_columns的a.position和a.owner = c上的JOIN user_constraints c。 owner和a.constraint_name = c.constraint_name在c.owner = b.owner和c.r_constraint_name = b.constraint_name和a.position = b.position上加入user_cons_columns b,其中c.constraint_type ='R'由a.constraint_name排序, a.table_name,a.column_name,b.table_name,b.column_name</li></ul>[/collapse]</div><hr>
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链接到Oracle数据库在线文档
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您可能想要浏览数据字典视图。他们有前缀:
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用户
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所有
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DBA
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样品:
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[cc lang="sql"]SELECT * FROM dictionary WHERE TABLE_NAME LIKE 'ALL%'继续Mike的示例,您可能希望生成脚本以启用/禁用约束。我只修改了第一行的'select'。
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8SELECT 'alter table ' || TABLE_NAME || ' disable constraint ' || CONSTRAINT_NAME || ';'
FROM all_constraints
WHERE constraint_type='R'
AND r_constraint_name IN
(SELECT constraint_name
FROM all_constraints
WHERE constraint_type IN ('P','U')
AND TABLE_NAME='<your table here>');
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9SELECT acc.table_name, acc.constraint_name
FROM all_cons_columns acc
INNER JOIN all_constraints ac
ON acc.constraint_name = ac.constraint_name
WHERE ac.r_constraint_name IN (
SELECT constraint_name
FROM all_constraints
WHERE TABLE_NAME='yourTable'
);
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19SELECT DISTINCT TABLE_NAME, constraint_name, column_name, r_table_name, POSITION, constraint_type
FROM (
SELECT uc.table_name,
uc.constraint_name,
cols.column_name,
(SELECT TABLE_NAME FROM user_constraints WHERE constraint_name = uc.r_constraint_name)
r_table_name,
(SELECT column_name FROM user_cons_columns WHERE constraint_name = uc.r_constraint_name AND POSITION = cols.position)
r_column_name,
cols.position,
uc.constraint_type
FROM user_constraints uc
INNER JOIN user_cons_columns cols ON uc.constraint_name = cols.constraint_name
WHERE constraint_type != 'C'
)
START WITH TABLE_NAME = '&&tableName' AND column_name = '&&columnName'
CONNECT BY nocycle
prior TABLE_NAME = r_table_name
AND prior column_name = r_column_name;
下载适用于10G的Oracle参考指南,其中介绍了数据字典表。
上面的答案很好,但请查看可能与约束相关的其他表格。
1SELECT * FROM DICT WHERE TABLE_NAME LIKE '%CONS%';最后,获取像Toad或SQL Developer这样的工具,它允许您在UI中浏览这些东西,您需要学习使用表格,但您也应该使用UI。