GROUP_CONCAT ORDER BY
我有一张桌子:
1 2 3 4 5 6 7 8 9 10 11 12 | +-----------+-------+------------+ | client_id | views | percentage | +-----------+-------+------------+ | 1 | 6 | 20 | | 1 | 4 | 55 | | 1 | 9 | 56 | | 1 | 2 | 67 | | 1 | 7 | 80 | | 1 | 5 | 66 | | 1 | 3 | 33 | | 1 | 8 | 34 | | 1 | 1 | 52 | |
我试过
1 2 3 4 5 6 7 8 | SELECT li.client_id, group_concat(li.views) AS views, group_concat(li.percentage) FROM li GROUP BY client_id; +-----------+-------------------+-----------------------------+ | client_id | views | group_concat(li.percentage) | +-----------+-------------------+-----------------------------+ | 1 | 6,4,9,2,7,5,3,8,1 | 20,55,56,67,80,66,33,34,52 | +-----------+-------------------+-----------------------------+ |
但我希望按顺序获取视图,例如:
1 2 3 4 5 | +-----------+-------------------+----------------------------+ | client_id | views | percentage | +-----------+-------------------+----------------------------+ | 1 | 1,2,3,4,5,6,7,8,9 | 52,67,33,55,66,20,80,34,56 | +-----------+-------------------+----------------------------+ |
您可以通过以下方式在
1 2 3 | SELECT li.client_id, group_concat(li.percentage ORDER BY li.views ASC) AS views, group_concat(li.percentage ORDER BY li.percentage ASC) FROM li GROUP BY client_id |
group_concat支持自己的order by子句
MySQL – The GROUP_CONCAT() function
所以你应该写:
1 2 3 | SELECT li.clientid, group_concat(li.views order by views) AS views, group_concat(li.percentage order by percentage) FROM table_views GROUP BY client_id |
尝试
1 2 3 4 | SELECT li.clientid, group_concat(li.views ORDER BY li.views) AS views, group_concat(li.percentage ORDER BY li.percentage) FROM table_views li GROUP BY client_id |
http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function%5Fgroup-concat
在IMPALA中,没有在GROUP_CONCAT中订购可能会在Coders'Co上出现问题。 我们有一些解决方法(我们需要它用于Rax / Impala)。 如果您需要在IMPALA中使用ORDER BY子句的GROUP_CONCAT结果,请查看此博客文章:http://raxdb.com/blog/sorting-by-regex/