关于c＃：Nhibernate：映射有条件的多对多关系？

Nhibernate: Mapping a conditional many-to-many relationship?

我有以下对象模型：

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public class Organizer
{
private int id;

public virtual int Id
{
get { return id; }
set { id = value; }
}

private string fullName ="";

public virtual string FullName
{
get { return fullName; }
set { fullName = value; }
}

private List<Email> emails = new List<Email>();

public virtual List<Email> Emails
{
get { return emails; }
set { emails = value; }
}
}

public enum EmailType
{
Primary, Secondary
}

public class Email
{
private int iD;

public virtual int ID
{
get { return iD; }
set { iD = value; }
}
private string emailAddress ="";

public virtual string EmailAddress
{
get { return emailAddress; }
set { emailAddress = value; }
}
private EmailType emailType = EmailType.Primary;

public virtual EmailType EmailType
{
get { return emailType; }
set { emailType = value; }
}

private List<Organizer> organizers;

public virtual List<Organizer> Organizers
{
get { return organizers; }
set { organizers = value; }
}
}

我有以下数据库模式：

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CREATE TABLE [dbo].[EmailAddresses](
[ID] [int] IDENTITY(1,1) NOT NULL,
[EmailAddress] [nvarchar](550) NULL
)

CREATE TABLE [dbo].[Organizers](
[ID] [int] IDENTITY(1,1) NOT NULL,
[FullName] [nvarchar](550) NULL
)

CREATE TABLE [dbo].[Organizers_PrimaryKeys](
[ID] [int] IDENTITY(1,1) NOT NULL,
[PrimaryKeyID] [int] NULL,
[PrimaryKeyTypeID] [int] NULL,
[OrganizerID] [int] NULL
)

现在，我有一个很严重的问题要解决，如何用NHibernate(不是流利的NHibernate)来映射这个问题。基本上，我希望它被映射，这样当我执行"session.save(anororganizer)"时，数据有时被写入两个表，有时被写入三个表。例如，假设我们有Organizera，他有三封电子邮件：email_1、email_2和email_3。email_1具有emailtype.primary，而其他两个具有emailtype.secondary。因此，当我们保存Organizera时，会发生以下情况：

Organisera的详细信息将写入表格组织者

email_1、email_2和email_3都会写入emailAddresses表(如果它们还不存在的话)

在Organizers的PrimaryKeys表中创建了一个新行，其中电子邮件的ID写为PrimaryKeyID，Organizera的ID写为OrganizerID(不要担心PrimaryKeyTypeID)。稍后我会解决的)。

那么我该如何描绘这种关系呢？到目前为止，我有以下几点：

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<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="BLL"
namespace="BusinessLogic">

<class name="Organizer" table="Organizers">
<id name="Id">
<column name="ID"/>
<generator class="native" />
</id>
<property name="FullName">
<column name="FullName"/>
</property>
<bag name="Emails" table="Organizers_PrimaryKeys" inverse="false" cascade="all" lazy="true">
<key column="Id"/>
<many-to-many class="Email" />
</bag>
</class>
</hibernate-mapping>

<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="BLL"
namespace="BusinessLogic">

<class name="Email" table="EmailAddresses">
<id name="ID">
<column name="ID"/>
<generator class="native" />
</id>
<property name="EmailAddress" unique="true" type="string">
<column name="EmailAddress"/>
</property>

</class>
</hibernate-mapping>

我不知道在email.hbm.xml中放什么来完成这个"有条件的"多对多关系。

您需要将主邮件和次邮件分离到两个不同的对象，因为它们不是同一种实体。将Organizer类添加到PrimaryEmail的一对一关系，并保留当前的多对多第二电子邮件列表。

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<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="BLL"
namespace="BusinessLogic">

<class name="Organizer" table="Organizers">
<id name="Id">
<column name="ID"/>
<generator class="native" />
</id>
<property name="FullName">
<column name="FullName"/>
</property>
<one-to-one name="PrimaryEmail" class="PrimaryEmail" />
<bag name="Emails" table="EmailAddresses" inverse="false" cascade="all" lazy="true">
<key column="Id"/>
<many-to-many class="SecondaryEmail" />
</bag>
</class>

<class name="PrimaryEmail" table="Organizers_PrimaryKeys">
<id name="ID">
<column name="ID"/>
<generator class="native" />
</id>
<property name="EmailAddress" unique="true" type="string">
<column name="EmailAddress"/>
</property>
</class>

<class name="SecondaryEmail" table="EmailAddresses">
<id name="ID">
<column name="ID"/>
<generator class="native" />
</id>
<property name="EmailAddress" unique="true" type="string">
<column name="EmailAddress"/>
</property>
</class>